The value of the side b and c will be 58.57 units and 36.86 units, and angle ∠B will be 107°.
Let the triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c.
Then by the sine law, we have
[tex]\rm \dfrac{\sin\angle A}{a} = \dfrac{\sin\angle B}{b} = \dfrac{\sin\angle C}{c}[/tex]
The sum of angles of triangle is 180°.
∠A + ∠B + ∠C = 180°
36° + ∠B + 37° = 180°
∠B = 107°
Then the side b will be
sin 36° / 36 = sin 107° / b
b = 58.57 units
Then the side c will be
sin 36° / 36 = sin 37° / c
c = 36.86 units
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