The value of x will be -7. The expression is solved using the identity.
Exponents can also be written as logarithms. The other number is equal to a logarithm with a number base. It's the exact inverse of the exponent function.
Given expression;
[tex]\rm log_2(\frac{1}{128}) = x[/tex]
The expression is solved using the identity as;
[tex]\rm log_e1 = x\\\ e^x=1[/tex]
Apply the identity;
[tex]\rm log_2(\frac{1}{128}) = x \\\\ 2^x = \frac{1}{128}\\\\ 2^x = \frac{1}{2^7} \\\\ 2^x = 2^{-7} \\\\ x = -7[/tex]
Hence the value of x will bed -7.
To learn more about the logarithm refer;
https://brainly.com/question/7302008
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