log2(1/128)=x, then x =

Sagot :

The value of x will be -7. The expression is solved using the identity.

What is the definition of a logarithm?

Exponents can also be written as logarithms. The other number is equal to a logarithm with a number base. It's the exact inverse of the exponent function.

Given expression;

[tex]\rm log_2(\frac{1}{128}) = x[/tex]

The expression is solved using the identity as;

[tex]\rm log_e1 = x\\\ e^x=1[/tex]

Apply the identity;

[tex]\rm log_2(\frac{1}{128}) = x \\\\ 2^x = \frac{1}{128}\\\\ 2^x = \frac{1}{2^7} \\\\ 2^x = 2^{-7} \\\\ x = -7[/tex]

Hence the value of x will bed -7.

To learn more about the logarithm refer;

https://brainly.com/question/7302008

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