An aqueous solution contains 0.21 M ammonium iodide. One Liter of this solution could be converted into a buffer by the addition of: (Assume that the volume remains constant as each substance is added.)

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Tutorconsortium302id Tutorconsortium302id · Answer 1

The ammonium iodide solution is converted into a buffer by the addition of ammonia (NH₃).

A solution which is formed by the addition of weak acid and its conjugate base or weak base and its conjugate acid.
They resist a change in pH of the solution when an acid or alkali added to them.

The given solution contains 0.21 M ammonium iodide (NH₄I). This is a salt of a weak base(NH₃) and a strong acid(HI).

NH₄I(s) → NH₃(g) + HI(g)

Where the salt is ionic. So, in aqueous solution it dissociates into NH₄⁺ and I⁻

The ammonium ion NH₄⁺ is the conjugate acid of the weak base NH₃.

So, the mixture of this weak base NH₃ and its conjugate acid NH₄⁺ converts the solution into a buffer.

Therefore, one liter of the given solution could be converted into a buffer by the addition of a weak base NH₃.

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