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A 0.08m long spring is attached vertically to the ceiling. after 66kg mass is attached to the spring it has a length of 2.1m. determine the spring's force constant. use g=10

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Answer:

The spring constant is 647.05 N/m.

Explanation:

The weight of the mass is W=mg

                                            W=66*10

                                            W=660

The spring force is given by the formula F=kx

where k is the spring force constant.

The spring force is equal to the weight of the mass. Therefore equate W and F.

kx= 660

k=660/x

Difference in length x=2.1-0.08= 1.02 m

k=660/1.02

k=647.05 N/m

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