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I need help on questions d and e, not sure how to solve!

I Need Help On Questions D And E Not Sure How To Solve class=

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D.

[tex]m(x) = 0 \\ - 3x = 0 \\ x = 0[/tex]

E.

[tex]m(x) = \frac{ - 3}{25} [/tex]

[tex] \frac{ - 3x}{x {}^{2} + 2x - 24} = \frac{ - 3}{25} [/tex]

[tex] - 3(x {}^{2} + 2x - 24) = - 3(x)(25) \\ divide \: both \: sides \: by - 3[/tex]

[tex]x {}^{2} + 2x - 24 = 25x[/tex]

[tex]x {}^{2} - 23x - 24 = 0[/tex]

[tex](x - 24)(x + 1) = 0 [/tex]

[tex]x = 24 \\ x = - 1[/tex]

Answer:

D

x=0

Step-by-step explanation:

E)

[tex]\frac{-3x}{x^2+2x-24} =\frac{-3}{25} \\x^2+2x-24=25x\\x^2+2x-25x-24=0\\x^2-23 x-24=0\\x^2-24x+x-24=0\\x(x-24)+1(x-24)=0\\(x-24)(x+1)=0\\x=24,-1[/tex]

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