The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)
4Hg + O₂ —> 2Hg₂O
From the balanced equation above,
4 moles of Hg reacted with 1 mole of O₂
From the balanced equation above,
4 moles of Hg reacted with 1 mole of O₂
Therefore,
12 moles of Hg will react with = 12 / 4 = 3 moles of O₂
From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.
Thus, Hg is the limiting reactant and O₂ is the excess reactant .
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