To draw a graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of a second point by going up 3 and over.
then draw a line through the points.


Sagot :

Thus, for drawing the graph for y = 3/4x + 7.

For drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.

How to know if a point lies in the graph of a function?

All the points (and only those points) which lie on the graph of the function satisfy its equation.

Thus, if a point lies on the graph of a function, then it must also satisfy the function.

For this case, the equation given to us is:

y=3/4x+7

Any equation of the form y=mx+c where m and c are constants and x and y are variables is the equation of a straight line.

For a straight line to be characterized, only two points are sufficient.

For x = 0, the y-coordinate would be such that it would satisfy the equation

y=3/4x+7

Putting x = 0, we get:

y=3/4(0)+7

y=7

Thus, the y-coordinate of the point on this line whose x-coordinate is 0 is 7. Thus, (0,7) is one of the point coordinates on the considered line.

Putting x = 3, we get:

y=3/4(3)+7

y=9.25

Thus, the y-coordinate of the point on this line whose x-coordinate is 0 is 9.25. Thus, (0,9.25) is another of the point's coordinates on the considered line.

Thus, for drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.

Learn more about points lying on the graph of a function here:

brainly.com/question/1979522

#SPJ1