Answer:
In the right triangle, the side a=[tex]4[/tex] and the hypotenuse c=[tex]7[/tex].
To find: the value of x
We have,
[tex]a=6[/tex] and [tex]c=7[/tex]
Now,by the pythagorean theorem,
[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]
Substitute the values,
[tex] {6}^{2} + {x}^{2} = {7}^{2} [/tex]
[tex]36 + {x}^{2} = 49[/tex]
Subtract 36 from each sides,
[tex] {x}^{2} = 13[/tex]
Take square root from each sides,
[tex]x = \sqrt{13} [/tex]
Hence, the value of x is [tex]\sqrt{13}[/tex].
