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Which of the following is the equation of the function below? y=2sec (x+pi/6)+2 y=sec2(x+pi/6)]+2 y=sec[2(x+2)] + pi/6 y=2sec(x+2) + pi/6

Which Of The Following Is The Equation Of The Function Below Y2sec Xpi62 Ysec2xpi62 Ysec2x2 Pi6 Y2secx2 Pi6 class=

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MrRoyalid

The equation of the function is y = sec(2(x + π/6)) + 2

How to determine the equation of the function?

From the graph, we have the following parameters:

  • Local maximum = 3
  • Local minimum = 1
  • Period = 2
  • Phase shift = π/6

A secant function is represented as:

y = A sec(b(x + c)) + d

Where:

A = 0.5 * (max - min) = 0.5 * (3 - 1) = 1

b = Period = 2

c = Phase shift = π/6

d = 0.5 * (max + min) = 0.5 * (3 + 1) = 2

So, we have:

y = 1 * sec(2(x + π/6)) + 2

Evaluate

y = sec(2(x + π/6)) + 2

Hence, the equation of the function is y = sec(2(x + π/6)) + 2

Read more about secant function at:

https://brainly.com/question/13276558

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