Answer:
Step-by-step explanation:
consider the events F and S :
F : «the first point is placed on JL»
S : «the second point is not placed on KL»
F∩S : «a point on JM is placed first on JL and a second point is not placed on KL»
[tex]p\left( F\right) =\frac{JL}{JM} =\frac{10}{16} =\frac{5}{8}[/tex]
[tex]p\left( \overline{S} \right) =\frac{KL}{JM} =\frac{6}{16} =\frac{3}{8}[/tex]
[tex]\Longrightarrow p\left( S\right) =1-p\left( \overline{S} \right) =1-\frac{3}{8} =\frac{5}{8}[/tex]
[tex]p\left( F\cap S\right) =p\left( F\right) \times p\left( S\right) =\frac{5}{8} \times \frac{5}{8} =\frac{25}{64}[/tex]