Answer:
5
Explanation:
Each digit in binary is worth double the amount compared to the number to the right of it. This means the rightmost number is 1, the second rightmost is 2, the third rightmost is 4, and so on.
If a digit has a 1 in the place, you add however much it is worth to the decimal count.
For example, this number has a 1 in the third rightmost. The third place here means a 4, so we add 4 to the count. It also has a 1 in the rightmost place, so we add 1 to the count.
Any digit with 0 is simply there to hold the place and can be ignored.
A bit confusing but hopefully you understand
