if I have a 71 percent in a class and I take a final worth 10 percent of my grade and fail. what would my grade be? thanks in advance.

Sagot :


61 percent that's the answer

I think you're asking for a numerical answer, but you didn't mention
your score on the final.

Since the final is worth 10% (one tenth) of the grade, that 71 that you
have going into the final is worth 9/10 of the grade. So the way you
calculate your overall average is

          Overall score = 1/10 of [ (71 x 9) + score on the final ] .

If you scored absolute zero on the final, your overall average would be

          Overall score = (1/10) x [ (71 x 9) + 0 ] = (1/10) (639) = 63.9% .

That's the lowest overall score for the class that you can have.

The highest overall score you could have would be if you got 100% on the final.
Then
         Overall = (1/10) x (639 + 100) = (1/10) x (739) = 73.9% .

If you got a 50% on the final, your overall would be

                         (1/10) x (639 + 50) = (1/10) x (689) = 68.9% .

In general, your overall score for the class, after the final, is going to be

           63.9%  plus  (1 tenth) of your score on the final.

Good luck !