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Convert √3+i to polar form.

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LammettHashid

Let z = √3 + i. Compute the modulus and argument of z :

|z| = √((√3)² + 1²) = √4 = 2

arg(z) = arctan(1/√3) = π/6 = 30°

Then

z = √3 + i = 2 (cos(30°) + i sin(30°))

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