Answer: (6, 16)
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Explanation:
The given equation is in the format y = ax^2 + bx+c
We have a = 2, b = -24, c = 88
The vertex is of the form (h,k)
h = -b/(2a)
h = -(-24)/(2*2)
h = 6
Plug this as the x value back into the original equation to find the y coordinate of the vertex. This would be the value of k.
y = 2x^2 - 24x + 88
y = 2(6)^2 - 24(6) + 88
y = 16
The vertex is located at (h,k) = (6, 16)
This is the lowest part of the parabola because it opens upward (note that a > 0).
The answer can be visually confirmed by using Desmos as shown in the screenshot below.
