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A bowl has 3 red beads and 7 blue beads. Two beads are selected at random one at a time. First a red bead is drawn and placed on a table. Next a blue bead is drawn.

What is the probability of this event?

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A Bowl Has 3 Red Beads And 7 Blue Beads Two Beads Are Selected At Random One At A Time First A Red Bead Is Drawn And Placed On A Table Next A Blue Bead Is Drawn class=

Sagot :

MrRoyalid

The probability that first a red bead is drawn and next a blue bead is drawn is 7/30,and both events are dependent

How to determine the probability?

The distribution of the beads are:

Red = 3

Blue = 7

Total = 10

The probability of selecting the red bead first is:

P(Red) = 3/10

When the red bead is selected, the number of beads becomes 9

So, the probability of selecting a blue bead is

P(Blue) = 7/9

The probability of the event is then calculated using:

P = 3/10 * 7/9

Evaluate

P = 7/30

Hence, the probability of the event is 7/30

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https://brainly.com/question/25638875

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