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a scientist prepares a solution by dissolving 25.22g of lithium fluoride (lif) in 2.2 liters of water. What would be the molarity of the solution?

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Msakerjid

Answer:

[tex]c = 0.441mol{dm}^{ - 1} [/tex]

Explanation:

[tex]m = 25.22g \\ v = 2.2l = 2.2 {cm}^{3} \\ mm(lif ) = 7 + 19 \\ = 26g {mol}^{ - 1} \\ number \: of \: moles(n) = \frac{m}{mm} \\ = \frac{25.22g}{26g {mol}^{ - 1} } \\ = 0.97mol \\ concetration(c) = \frac{n}{v} \\ = \frac{0.97mol}{2.2 {cm}^{3} } \\ c = 0.441mol {dm}^{ - 3} [/tex]

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