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3. Calculate the [H+], POH, and [OH-] for the following solutions:

a) (10 Points) pH 2. 90 (the approximate pH of lemon juice

b) (10 Points) pH 3. 86 (the approximate pH of sauerkraut)

c) (10 Points) pH 10. 81 (the approximate pH of milk of magnesia)

d) (10 Points) pH 4. 11 (the approximate pH of orange juice)

e) (10 Points) pH 11. 61 (the approximate pH of household ammonia)

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The  pH refers to the negative logarithm of the hydrogen ion concentration of a solution.

What is pH?

The term pH refers to the negative logarithm of the hydrogen ion concentration of a solution. Let us now solve each question.

a) Since pH = 2.90

[H^+] = Antilog(-2.90) = 1.26 * 10^-3 M

[OH^-] = 1 * 10^-14/ 1.26 * 10^-3 = 7.9 * 10^-12 M

pOH = 14 - 2.90 = 11.1

b) Since pH = 3. 86

[H^+] = Antilog(-3.86) = 1.38 * 10^-4 M

[OH^-] = 1 * 10^-14/ 1.38 * 10^-4 = 7.2 * 10^-11 M

pOH =  14 - 3.86 = 10.14

c)Since pH = 10.81

[H^+] = Antilog(-10.81) = 1.55 * 10^-11 M

[OH^-] = 1 * 10^-14/ 1.55 * 10^-11 = 6.5 * 10^-4 M

pOH = 14 -  10.81 = 3.19

d) Since pH = 4.11

[H^+] = Antilog(-4.11) = 7.8 * 10^-5 M

[OH^-] = 1 * 10^-14/7.8 * 10^-5 = 1.3 * 10^-10M

pOH = 14 - 4.11 = 9.89

e) Since pH = 11.61

[H^+] = Antilog(-11.61) =2.45 * 10^-12 M

[OH^-] = 1 * 10^-14/2.45 * 10^-12 = 4.1 * 10^-3 M

pOH = 14 - 11.61 = 2.39

Learn more about pH:https://brainly.com/question/15289741

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