The endpoints of a
diameter of a circle are (2,
4) and (-4, 7). What is the
standard form of the
equation
of this circle?

I know one of the answer is not c

Hurry i got like 30 mins left and a girl is tired


The Endpoints Of A Diameter Of A Circle Are 2 4 And 4 7 What Is The Standard Form Of The Equation Of This Circle I Know One Of The Answer Is Not C Hurry I Got L class=

Sagot :

Answer:

2nd option

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

the centre is at the midpoint of the endpoints of the diameter.

The coordinates of the centre is the average of the coordinates of the endpoints.

centre = ( [tex]\frac{-4+2}{2}[/tex], [tex]\frac{7-1}{2}[/tex] ) = ([tex]\frac{-2}{2}[/tex] , [tex]\frac{6}{2}[/tex] ) = (- 1, 3 )

the radius is the distance from the centre to either of the endpoints

using the distance formula to calculate r

r = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2[/tex]

with (x₁, y₁ ) = (- 1, 3 ) and (x₂, y₂ ) = (2, - 1 )

r = [tex]\sqrt{(2-(-1))^2+(-1-3)^2}[/tex]

  = [tex]\sqrt{(2+1)^2+(-4)^2}[/tex]

  = [tex]\sqrt{3^2+16}[/tex]

  = [tex]\sqrt{9+16}[/tex]

  = [tex]\sqrt{25}[/tex]

   = 5

then equation of circle is

(x - (- 1) )² + (y - 3)² = 5² , that is

(x + 1)² + (y - 3)² = 25