Sagot :
Answer:
1 solution
- x = -6
Explanation:
[tex]\rightarrow \sf y=x^2+12x+36[/tex]
[tex]\rightarrow \sf x^2+12x+36=0[/tex]
[tex]\rightarrow \sf x^2+6x+6x+36=0[/tex]
[tex]\rightarrow \sf x(x+6)+6(x+6)=0[/tex]
[tex]\rightarrow \sf (x+6)(x+6)=0[/tex]
[tex]\rightarrow \sf x=-6[/tex]
Hence there is only one solution for this quadratic equation and the value is -6
[tex]\\ \rm\rightarrowtail x^2+12x+36=0[/tex]
[tex]\\ \rm\rightarrowtail x^2+6x+6x+36=0[/tex]
[tex]\\ \rm\rightarrowtail (x+6)(x+6)=0[/tex]
Only one solution present
x=-6