The average rate at which the population is growing over the interval 0≤d≤7 is 1228, while the exponential function as a function of hours is [tex]p(h)=400(1.56)^{\frac{h}{24} }[/tex]
An exponential function is in the form:
y = abˣ
Where a is the initial value and b is the multiplication factor.
Let p represent the population of the bacteria after d days.
[tex]P(d)=400(1.56)^d\\\\P(7)=400(1.56)^7=8994\\\\P(0)=400\\\\\\Average\ rate\ of\ change=\frac{P(7)-P(0)}{7-0}=\frac{8994-400}{7-0} =1228[/tex]
b) 24 hours = 1 day, hence:
[tex]p(h)=400(1.56)^{\frac{h}{24} }[/tex]
The average rate at which the population is growing over the interval 0≤d≤7 is 1228, while the exponential function as a function of hours is [tex]p(h)=400(1.56)^{\frac{h}{24} }[/tex]
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