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A body of mass 5kg is ejected vertically from the ground when a force of 600N acts on it for 0.1s.Calculate the velocity with which the body leaves the ground.​

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Alexanderorangeguyid

1200

Explanation:

F = m x (v / t)

v / t = F / m

v = (F / m) / t

v = (600 / 5) / 0.1

v = 120 / 0.1

v = 1200 m / s

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