[tex]y = - x {}^{2} + 6x - 15[/tex]
[tex]y {}^{ \gamma } = - 2x + 6[/tex]
[tex]y {}^{ \gamma } = 0[/tex]
[tex] - 2x + 6 = 0[/tex]
[tex] - 2x = - 6[/tex]
[tex]2x = 6[/tex]
[tex]x = 3[/tex]
[tex]y = - (3) {}^{2} + 6(3) - 15[/tex]
[tex]y = - 9 + 18 - 15[/tex]
[tex]y = - 9 + 3[/tex]
[tex]y = - 6[/tex]
[tex]==============================[/tex]
In order to find the vertex of a parabola, we use the following formula:
[tex]\mathfrak{\displaystyle\frac{-b}{2a} }[/tex]
Please remember that a parabola looks like this:
[tex]\tt{y=ax^2+bx+c}[/tex]
Now you know what a and b stand for.
In this case, a = -1, and b is 6:
[tex]\mathfrak{\displaystyle\frac{-6}{2(-1)} }[/tex]
Simplify:
[tex]\mathfrak{\displaystyle\frac{-6}{-2}}[/tex]
[tex]\mathfrak{3}\\=======================================[/tex]
[tex]\mathcal{DiAmOnD}\\\tt{A~Creative~Helper}}}}[/tex]
