The work done by the man pushing the car over the given distance is 1000J.
Given the data in the question;
Work done; [tex]W = \ ?[/tex]
Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
[tex]Work\ done = f * d[/tex]
Where f is force applied and d is distance travelled.
To determine the work done by the man, we first solve for the force applied F.
From Newton's Second Law; [tex]Force \ F = m * a[/tex]
We substitute our given values into the expression
[tex]F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2[/tex]
Next we substitute our values into the expression of work done above.
[tex]Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J[/tex]
Therefore, the work done by the man pushing the car over the given distance is 1000J.
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