Abby is shooting a rocket off the top of a 128 foot tall building at a velocity of 96 feet per second. The equation to represent this is h(t) = -16t? +960 + 128 where h(t) represents the height of the rocket and t is the time after takeoff.

What is the maximum height of the rocket?
How many seconds does ot take to get to the maximum height?
Find the time it takes (in seconds) for the rocket to crash to the ground.​


Sagot :

Answer:

  a) 272 feet

  b) 3 seconds

  c) 7.123 seconds

Step-by-step explanation:

A graphing calculator provides an easy way to answer questions about the parameters of a quadratic function. Here the graph shows ...

a) the maximum height is 272 feet

b) it takes 3 seconds to get there

c) the rocket crashes after about 7.123 seconds

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You can solve this algebraically by rewriting the equation in vertex form.

  h(t) = -16t² +96t +128 . . . . . . given

  h(t) = -16(t² -6t) +128 . . . . . . . factor out leading coefficient

  h(t) = -16(t² -6t +9) +128 -(-16)(9) . . . . complete the square

  h(t) = -16(t -3)² +272 . . . . . . write in vertex form

The vertex of the height function is (3, 272) meaning the rocket reaches a maximum height of 272 feet after 3 seconds.

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The zero of the function can be found to be ...

  0 = -16(t -3)² +272

  0 = (t -3)² -17 . . . . . . divide by -16

  t -3 = ±√17 . . . . . . add 17, take the square root

  t = 3 +√17 ≈ 7.123106 . . . . . positive time value for h(t) = 0

It takes about 7.12 seconds for the rocket to crash.

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