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What is the zero of the function?
f (x) = x2+x-42/x2+3x-28
Enter your answer in the box.

NEED HELP What Is The Zero Of The Function F X X2x42x23x28 Enter Your Answer In The Box class=

Sagot :

[tex]f(x)=\cfrac{x^2+x-42}{x^2+3x-28}\implies \stackrel{f(x)}{0}=\cfrac{x^2+x-42}{x^2+3x-28}\implies 0 = x^2+x-42 \\\\\\ 0=(x+7)(x-6)\implies x= \begin{cases} 6\\ -7 \end{cases}[/tex]

Wimab46id
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6.3630657
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1.38899554
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4.75206125