[tex]\qquad\qquad\huge\underline{{\sf Answer}}☂[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + 8x = 33 [/tex]
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + 8x +16 = 33 + 16 [/tex]
[tex]\qquad \sf \dashrightarrow \: (x + 4) {}^{2} = 49[/tex]
[tex]\qquad \sf \dashrightarrow \: x + 4 = \sqrt{49} [/tex]
[tex]\qquad \sf \dashrightarrow \: x + 4 = \pm7[/tex]
Hence, there are two solutions ~
[tex]\qquad \sf \dashrightarrow \: x + 4 = 7[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 7 - 4[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 3[/tex]
[tex]\qquad \sf \dashrightarrow \: x + 4 = - 7[/tex]
[tex]\qquad \sf \dashrightarrow \: x = - 7 - 4[/tex]
[tex]\qquad \sf \dashrightarrow \: x = - 11[/tex]
I hope you understood ~