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The sum of two numbers is 94. The larger number is 8 less than twice the smaller number. What is the larger number?

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Naǫid
x - the larger number
y - the smaller number

The larger number is 8 less than twice the smaller number:
[tex]x=2y-8[/tex]
So the larger number is 2y-8.

The sum of the two numbers is 94.
[tex]2y-8+y=94 \\ 2y+y=94+8 \\ 3y=102 \\ y=\frac{102}{3} \\ y=34[/tex]
The smaller number is 34.

[tex]x=2y-8=2 \times 34-8=68-8=60[/tex]
The larger number is 60.
ValyRemusid
[tex]a+b=94[/tex]

[tex]a>b[/tex] ⇒ [tex]a=2b-8[/tex]

[tex]\hbox{We will introduce this in the first, original equation} : 2b-8+b=94[/tex]

[tex]3b=102[/tex] ⇒ [tex]b= \frac{102}{3} [/tex] ⇒ [tex]\boxed{b=34}[/tex]

[tex]a=94-34[/tex] ⇒ [tex]\boxed{a=60}[/tex]

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