A human lung at maximum capacity has a volume of 3. 0 liters. If the partial pressure of oxygen in the air is 21. 1 kilopascals and the air temperature is 295 K, how many moles of oxygen are in the lung?.

Sagot :

The ideal gas equation gives the relation of the pressure and the volume of the gas with that of the moles and the temperature. Moles of oxygen in the lung are 0.026 moles.

What is the ideal gas equation?

The ideal gas equation states that moles of the substances are directly proportional to the pressure and volume but inversely to the temperature of the hypothetical gas.

The ideal gas equation can be given as,

[tex]\rm PV = nRT[/tex]

Where,

Volume or the lung capacity (V) = 3.0 L

Pressure of the lungs (P) = 0.208 atm  

Gas constant (R) = 0.082057

Temperature of the air (T) = 295 K

Substituting values in the equation:

[tex]\begin{aligned}\rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{0.208 \times 3.0}{0.082057\times 295}\\\\&= 0.026 \;\rm moles\end{aligned}[/tex]

Therefore, the number of the moles of the oxygen in lungs are 0.026 moles.

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