[tex]leg : \ y =6 \m , \ \ leg : \ y =? \ \ hypotenuse : c = ?\ \ P = 36 \ m^2 \\ \\P=\frac{1}{2}xy\\ \\36=\frac{1}{\not2^1}*x*\not6^3\\ \\3x=36 \ \ /:3\\ \\x=12 \ m[/tex]
[tex]hypotenuse : \\ \\ c^2=x^2+y^2\\ \\c^2=12^2+6^2 \\ \\c^2 = 144+36 \\ \\c^2=180 \\ \\c=\sqrt{180}\\ \\c=\sqrt{36*5}\\ \\c=6\sqrt{5} \ m \\ \\Answer : the length of the hypotenuse of a right triangle is: 6\sqrt{5} \ m[/tex]
