Safawi kicked a ball with an initial speed of 20 ms-1 at 30º angle. If the ball experienced a constant vertical acceleration of -9.81 ms-2, calculate the ball’s maximum height and distance. Explain how soccer player could apply the force of summation theory to optimize his kicks performance.​

Sagot :

The maximum height of the ball is 5.1 m.

The horizontal distance or range of the ball is 35.4 m.

Maximum height of the ball

The maximum height attained by a projectile is the total vertical height reached by the projectile during the upward motion.

The maximum height of the ball is calculated as follows;

[tex]h = \frac{v^2 sin^2 \theta }{2g} \\\\h = \frac{(20)^2 \times (sin30)^2}{9.81} \\\\h = 5.1 \ m[/tex]

Distance of the ball

The horizontal distance or range of the ball is calculated as follows;

[tex]R = \frac{v^2 sin2\theta }{g} \\\\R= \frac{(20)^2 \times sin( 2\times 30)}{9.8} \\\\R =35.4 \ m[/tex]

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