2. A powerful experimental sewing machine is powered by a mass-spring system. This
sewing machine is capable of stitching 1,500 stiches in one minute.
a. How many stitches can this machine stitch is one second?
i. This is a measure of the sewing machine’s period or frequency?
b. If the sewing machine has a spring constant of 0.5 N/m, how large is the mass
that powers the oscillation motion of the machine? (Don’t forget to find T first)
Knowns Unknowns Formula

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Okpalawalter8id Okpalawalter8id · Answer 1

We have that the Number of stitches per sec and he mass of oscillation motion is mathematically given as

a) Nt=25stitches per sec

b) m=2.033e-5kg

Question Parameters:

This sewing machine is capable of stitching 1,500 stiches in one minute.

If the sewing machine has a spring constant of 0.5 N/m,

Generally the equation for the Number of stitches per sec is mathematically given as

Nt=N/t

Therefore

Nt=1500/60

Nt=25stitches per sec

b)

Generally the equation for the Time t is mathematically given as

[tex]T=2\pi\sqrt{\frac{m}{k}}[/tex]

Therefore

[tex]0.04=2\pi\sqrt{\frac{m}{0.5}}\\\\m=\frac{0.5*0.04^2}{4\pi^2}[/tex]

m=2.033e-5kg

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