Sagot :
Sinx = opps/hyp = 1/2
2^2 = 1^2 + x^2
x = sqrt(3) = adj
Cosx = adj/hyp = sqrt(3)/2
2^2 = 1^2 + x^2
x = sqrt(3) = adj
Cosx = adj/hyp = sqrt(3)/2
Value of cos x = ( √3 / 2) for 0° < x° < 90°.
What are trigonometric function?
" Trigonometric function is defined as the relation between sides and angles of a right angled triangle."
Formula used
(Hypotenuse)² = ( Opposite side)² + ( Adjacent side)²
sinθ = (Opposite side) / (Hypotenuse)
cosθ = (Adjacent side) / (Hypotenuse)
According to the question,
Given,
0° < x° < 90°
sin x = 1 / 2
Substitute the value in the formula we get,
Opposite side = 1
Hypotenuse = 2
(2)² = (1 )² + (Adjacent side)²
⇒(Adjacent side)² = 4 - 1
⇒ Adjacent side = ±√3
0° < x° < 90°
cos x >0
Therefore,
cos x = √3 / 2
Hence, value of cos x = ( √3 / 2) for 0° < x° < 90°.
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