Statement:
A non-deformed spring is 15 cm long. When a 2.0 N force is applied to it, its length becomes 19 cm.
To find out:
The spring constant of the spring.
Solution:
- Extension of the spring (x)
- = (19 - 15) cm
- = 4 cm
- = 0.04 m [since we have to find the answer in N/m]
- Let the spring constant of the spring be k.
- We know, the formula of spring force, i.e.,
- F = kx
- Putting the values in the above formula, we get
- 2 N = k × 0.04 m
- or, k = 2 N ÷ 0.04 m
- or, k = 50 N/m
Answer:
The spring constant of this spring is 50 N/m.
Hope you could understand.
If you have any query, feel free to ask.
