What is the volume of a 3.00M(mol/L) solution made with 122g of LiF?

Sagot :

moles is equal to mass over molar mass

122g/25.94 (25.94 is the molar mass of LiF)

3 = (4.703/L)

L = 1.567

1.567  L is the volume of a 3.00M(mol/L) solution made with 122g of LiF.

Define molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

Firstly calculate the moles of  LiF.

Moles = [tex]\frac{mass}{molar \;mass}[/tex]

Moles = [tex]\frac{122g}{25.94}[/tex]. (25.94 is the molar mass of LiF)

Moles = 4.703

Now find the volume:

[tex]Molarity = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]3.00M = \frac{4.703}{Volume \;of \;solution \;in \;litre}[/tex]

V = 1.567 L

Hence, 1.567 L is the volume of a 3.00M(mol/L) solution made with 122g of LiF.

Learn more about molarity here:

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