Sagot :
[tex]\frac{6x-1}{5}=\frac{3}{1} \ \ \ |\hbox{cross multiply} \\
6x-1=3 \times 5 \\
6x-1=15 \\
6x=15+1 \\
6x=16 \\
x=\frac{16}{6} \\
x=\frac{8}{3} \\
x=2\frac{2}{3}[/tex]
In order to solve for x, you need to isolate the x on one side. First, you need to multiply the 5 onto the other side to get rid of the fraction. Then, just add 1 and divide by 6 to isolate the x (steps will be shown below):
[tex]\frac{6x-1}{5}=\frac{3}{1}\\5(\frac{6x-1}{5})=5(3)\\6x-1=15\\6x-1+1=15+1\\6x=16\\6x/6=16/6\\x=\frac{16}{6}=\frac{8}{3}[/tex]
So, x = 8/3
[tex]\frac{6x-1}{5}=\frac{3}{1}\\5(\frac{6x-1}{5})=5(3)\\6x-1=15\\6x-1+1=15+1\\6x=16\\6x/6=16/6\\x=\frac{16}{6}=\frac{8}{3}[/tex]
So, x = 8/3