Sagot :
We know that he took 5 tests, mean is equal 90 so we know that following equations will be true if x will be sum of 5 scores:
[tex]\frac{x}{5}=90[/tex]
[tex]x=450[/tex]
Also we have to remember that max points that he could get is 100 so to find the lowest score he could get we have to do equation like this
[tex]\frac{100+y}{2}=90[/tex]
[tex]100+y=180[/tex]
[tex]y=80[/tex]
[tex]\frac{x}{5}=90[/tex]
[tex]x=450[/tex]
Also we have to remember that max points that he could get is 100 so to find the lowest score he could get we have to do equation like this
[tex]\frac{100+y}{2}=90[/tex]
[tex]100+y=180[/tex]
[tex]y=80[/tex]
If the Mean = 90 for 5 test values
it means that there was a variation of values between maximum i-e 100 and minimum that may be any number not known.
The possible minimum value is when 4 tests result in 100 and the 5th is unknown
it means
Mean = [(4X 100)+x] / 5
90 = (400+x) / 5
400 + x = 90 X 5
x = 450 -400 = 50
So the minimum possible test result is 50.
it means that there was a variation of values between maximum i-e 100 and minimum that may be any number not known.
The possible minimum value is when 4 tests result in 100 and the 5th is unknown
it means
Mean = [(4X 100)+x] / 5
90 = (400+x) / 5
400 + x = 90 X 5
x = 450 -400 = 50
So the minimum possible test result is 50.