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Using solving systems by substitution, how do you solve
Y=5x-7
6x-5y=12 Solve for x and y (x,y)

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[tex]y=5x-7 \\ 6x-5y=12 \\ \\ \hbox{substitute 5x-7 for y in the 2nd equation:} \\ 6x-5(5x-7)=12 \\ 6x-25x+35=12 \\ 6x-25x=12-35 \\ -19x=-23 \\ x=\frac{-23}{-19} \\ x=\frac{23}{19} \\ \\ y=5x-7=5 \times \frac{23}{19}-7=\frac{115}{19}-\frac{133}{19}=-\frac{18}{19} \\ \\ (x,y)=(\frac{23}{19},-\frac{18}{19})[/tex]