Answered

It takes A 12 hours alone, B 14
hours alone, and C 21 hours alone
to move the goods in a
warehouse. The three of them
work together at the beginning,
but A left in the middle of the
day.
It took a total of 7 hours for
them to finish.How many hours
did A work?
PLEASE HELP MY TEACHER WANTS THE WORK AND THIS IS WORTH HALF OUR GRADES1
A. 1
B. 2
C. 4
D. 5

Sagot :

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Answer:

D. 5

12 - 7 = 5

just shoot the answer . i dont know actually

Answer: B) 2

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Explanation:

List out the multiples of each number until we find the LCM

  • multiples of 12 are: 12, 24, 36, 48, 60, 72, 84, 96, ...
  • multiples of 14 are: 14, 28, 42, 56, 70, 84, 98, ...
  • multiples of 21 are: 21, 42, 63, 84, 105, ...

We see that 84 shows up in the list and it is the smallest such common item. The LCM of the numbers {12,14,21} is 84.

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Let's say there are 84 items to be moved in the warehouse.

  • If person A works alone, then their unit rate is 84/12 = 7 items per hour
  • If person B works alone, then their unit rate is 84/14 = 6 items per hour
  • If person C works alone, then their unit rate is 84/21 = 4 items per hour

We divide 84 over the respective time values given by your teacher, to find each unit rate.

Let x be the the length of time (in hours) that person A worked. They work alongside persons B and C to get a combined unit rate of 7+6+4 = 17 items per hour. This assumes no worker gets in the way of any others. They work the most efficiently together.

After x hours, they manage to move 17x items in the warehouse.

After x hours are up, there are 84-17x items left to move. Person A leaves B and C to finish up, so B and C's combined rate is 6+4 = 10 items per hour. These two remaining people move the 84-17x items at a rate of 10 items per hour. The time span they have left is 7-x hours.

This means we can form the following equation

(84-17x)/(10) = 7-x

Divide the number of items over the unit rate to find the time duration in hours.

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Solve for x

(84-17x)/(10) = 7-x

84-17x = 10(7-x)

84-17x = 70-10x

84-70 = -10x+17x

14 = 7x

7x = 14

x = 14/7

x = 2

Person A works for 2 hours

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If person A worked for 2 hours, then persons A,B,C moved 17*2 = 34 items. This leaves 84-34 = 50 items left. Person A takes off to leave persons B and C to handle the rest of the job. These two remaining people have a combined rate of 10 items per hour. So they take 50/10 = 5 hours when person A leaves. That gives the 2+5 = 7 hours total. This confirms the correct answer.

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