Find the slope of an equation f(x)=-3sqrt(x) at the point (9,-9)

Sagot :

Answer:

Slope is [tex]-\frac{1}{2}[/tex]

Step-by-step explanation:

Given:

[tex]f(x)=-3\sqrt{x}[/tex]

Find the derivative using the product rule:

[tex]f'(x)=\frac{d}{dx}(-3)*\sqrt{x}+-3*\frac{d}{dx}\sqrt{x}[/tex]

[tex]f'(x)=-3*\frac{1}{2\sqrt{x}}[/tex]

[tex]f'(x)=\frac{-3}{2\sqrt{x}}[/tex]

Plug in coordinates to find slope at that point:

[tex]f'(9)=\frac{-3}{2\sqrt{9}}=\frac{-3}{2(3)}=\frac{-3}{6}=-\frac{1}{2}[/tex]

Therefore, the slope of the equation at the point (9,-9) is [tex]-\frac{1}{2}[/tex].

Answer:

Step-by-step explanation:

f(x) = -3√x

f'(x) = -1.5/√x

f'(x) = -1.5/√9

f'(x) = -1.5/3

f'(x) = -0.5