The sled was launched with a velocity of 26.24 m/s
We'll begin by calculating the the time taken for the sled to land
Height (h) = 39 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
[tex]t = \sqrt{ \frac{2h}{g}} \\ \\t = \sqrt{ \frac{2 \times 39}{9.8}} \\ \\ t = 2.82 \: s \\ \\ [/tex]
- Finally, we shall determine the velocity.
Time (t) = 2.82 s
Horizontal distance (s) = 74 m
Horizontal velocity (u) =?
[tex]u = \frac{s}{t} \\ \\ u= \frac{74}{2.82} \\ \\ u = 26.24 \: m/s \\ \\ [/tex]
Therefore, the sled was launched with a velocity of 26.24 m/s
Learn more: https://brainly.com/question/25808490
