Solve |x| < 5

{x|-5 < x < 5}
{x|x < -5 or x > 5}
{-5, 5}


Sagot :

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is |x|

For the Negative case we'll use -(x)

For the Positive case we'll use (x)

-(x) < 5

Multiply

-x < 5

Multiply both sides by (-1)

Remember to flip the inequality sign

x > -5

Which is the solution for the Negative Case

(x) < 5

Which is the solution for the Positive Case

(-5,5)

[tex]One \: solution \: was \: found :  \\ -5 < x < 5[/tex]