Sagot :
Answer:
C [tex]\displaystyle x = 15[/tex]
Step-by-step explanation:
Use the Pythagorean Theorem to define the hypotenuse:
[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ 12^2 + 9^2 = x^2 \hookrightarrow 144 + 81 = x^2 \hookrightarrow \sqrt{225} = \sqrt{x^2} \\ \\ \boxed{15 = x}[/tex]
I am joyous to assist you at any time.
[tex] \huge \underline\text{ Hello There}[/tex]
[tex] \text{We know, Pythagoras Theorem}[/tex]
[tex]\implies \text{ (Hypotenuse)²= (Base)² + (Altitude)²}[/tex]
[tex] \text{Here, \red{Hypotenuse}= x, \red{Base}= 9, \red{Altitude}= 12}[/tex]
[tex] \underline \text{To Find, } \text{Value of'x'}[/tex]
[tex] \huge \underline\text \red {Solution}[/tex]
[tex](x) {}^{2} = (9) {}^{2} + ({12})^{2} \\ \implies (x) { }^{2} = 81 + 144 \\ \implies (x) {}^{2} = 225 \\ \implies x = \sqrt{225} \\ \implies x = 15[/tex]
[tex] \tt{So \: The \: Value \: of'x'= 15}[/tex]
[tex] \bold{\therefore Hypotenuse= 15}[/tex]
[tex] \text{Correct Opt. C= x =15}[/tex]