Answer:
2CHCl3 + 5/2 O2 => 2CO2 + H20 + 3Cl2
Explanation:
Left Hand Side(LHS)
We have CHCl3 and O2
Right Hand Side(RHS)
We have CO2, H2O and Cl2
Balancing
To make sure that they have same values, put 2 before CHCl3 giving 2CHCl3 and 3 on Cl2(RHS) for chlorine gas giving 3Cl2
H2O remains the same
Before CO2 put 2 giving 2CO2
To make sure that oxygen is balanced put 5/2 before it. This gives 5/2 O2 (2 cancels out don't worry)
Combining all;
2CHCl3 + 5/2 O2 => 2CO2 + H20 + 3Cl2
I hope this helps. Have a nice studies.
