3)A ball is kicked from a height of 2 feet off the ground, after 1 second the ball rea
nes a height
A ball is kicked from a height of 2 feet off the ground. After 1 second the ball reaches a height of 22 feet, and it reaches its maximum height of 38 feet after 3 seconds.
• Write the quadratic equation that represents the height of the ball at any given time
• Find the height of the ball at 4 seconds
Solve the following quadratic equations


Sagot :

Answer:

y = - 2x + (1/2 38) + 2   = y =  -2x + 19x + 2  at any second  and y = -2x^2 / 2  + 19/2 + 2/2 = - x^2 + 19/2 + 2 =  - x (4) + 19/2(4) + 1 = -4+ 38 + 1 = 35 seconds  

Step-by-step explanation:    We see that 38-2ft = 36ft and y intercept  = 2 and then -2x allows us to represent the starting point 2 as -2 (1) to allow a descend to our back to 0 for y  one we find y intercept we know - x^2  is our simplified equation and an input into this to find the static and slowed descend back to 0  if you keep inputting at 5 and 6 you see the equation speed up   Anyway at (4) substitute = 4 seconds we divide our simplified equation a = -x2 into  a b c and divide each by 2  before working out the decline of the equation (as equation still represents all ascending and descending) for the 4th second as the height was already said to be at its max at 38 feet see equation in answer to find 4 as substitute for x