Sagot :
The time required for the ball to roll down the given distance is 4 seconds.
Given the data in the question;
Since the ball started from rest,
- Initial velocity; [tex]u = 0[/tex]
- Acceleration; [tex]a = 5.0m/s^2[/tex]
- Distance traveled; [tex]s = 40m[/tex]
- Time taken; [tex]t =\ ?[/tex]
To determine the time required for the ball to travel the given distance, we use the Second Equation of Motion:
[tex]s = ut + \frac{1}{2}at^2[/tex]
Where s is distance traveled, u is initial velocity, a is acceleration and t is time taken.
We substitute our given values into the equation and solve for "t"
[tex]40m = [ 0*t ] + [ \frac{1}{2}\ *\ 5.0m/s^2\ *\ t^2 ]\\\\40m = 2.5m/s^2\ *\ t^2\\\\t^2 = \frac{40m}{2.5m/s^2}\\\\t^2 = 16s^2\\\\t = \sqrt{16s^2}\\\\t = 4s[/tex]
Therefore, the time required for the ball to roll down the given distance is 4 seconds.
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