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A pendulum bob is displaced from equilibrium and held where its height is
h = 14.6cm above its equilibrium position. If the bob is released, how fast will it be moving when it crosses the lowest point of its swing?

Sagot :

Answer:

Explanation:

the gravity potential energy will convert to kinetic energy in the absence of friction.

½mv² = mgh

v = √(2gh)

v = √(2(9.81)(0.146))

v = 1.69 m/s

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