Sagot :
the multiples of 3 in that case are 3, 6, and 9
so the probability is 3/10
so the probability is 3/10
There are ten numbers from 1-10
If there are ten numbers from 1-10, then there is a [tex] \frac{1}{10} [/tex] of a single random number being chosen.
There are three multiples of three (including 3): 3, 6, and 9
So if there are three multiples of three, its probability is [tex] \frac{3}{10} [/tex] or 3:10
The answer of choosing a multiple of three is 3:10
If there are ten numbers from 1-10, then there is a [tex] \frac{1}{10} [/tex] of a single random number being chosen.
There are three multiples of three (including 3): 3, 6, and 9
So if there are three multiples of three, its probability is [tex] \frac{3}{10} [/tex] or 3:10
The answer of choosing a multiple of three is 3:10