Sagot :
The average rate of growth of the ice can be found by dividing the thickness by the number of days of growth
The growth rate of the ice over the 8 days is 0.375 inches/day
Reason:
The known information on the ice are;
The time it took the ice to reach a thickness of 3 inches = 8 days
Required:
The (average) rate that the ice is growing in c=inches per day
Solution:
[tex]Rate \ of \ growth \ of \ ice= \dfrac{Increase \ in \ thickness}{ Time} = \dfrac{\Delta \ Thickness}{\Delta T}[/tex]
Therefore;
[tex]Rate \ of \ growth \ of \ ice= \dfrac{3 \ inches}{ 8 \ days} = 0.375 \ inches/day[/tex]
The (average) rate of growth of the ice over the 8 days is 0.375 inches per day
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