Answer:
13 in. ×8 in.
Step-by-step explanation:
Perimeter of rectangle= 2(length +width)
Let the length be L in. and the width be W in.
Given: perimeter= 42 in.,
W= L -5 -----(1)
42= 2(L +W)
Divide both sides by 2:
21= L +W -----(2)
Substitute (1) into (2):
21= L +L -5
21= 2L -5
2L= 21 +5
2L= 26
L= 26 ÷2
L= 13
Substitute L= 13 into (1):
W= 13 -5
W= 8
Width= 8 in.
Length= 13 in.
Therefore, the dimensions of the rectangle is 13 in. ×8 in.
