Answer:
1) 35 gallons by the first car 2) 40 gallons by the second car
Step-by-step explanation:
Suppose the first car used x gallons, when the second car used the rest- 75-x
If the first car's efficiency is 35 miles per galon, its milleage is 35*x, the second car's milleage is 15*(75-x). And the summary milleage is equal to 1825.
35x+15(75-x)=1825
35x+1125-15x= 1825
20x=700
x=35- gallons consumed by the first car,
75-35=40- gallons consumed by the second one